Math Forum :: View topic – area

Let 3 sides of a triangle be a,b,c respectively. Since the minimum difference of two prime numbers is 2, the length of a side cannot be 2. Thus, all sides should be odd primes. It is obvious that (a+b+c),(a+b-c),(b+c-a) and (c+a-b) are all odd numbers. Considering Heron’s Formula, Area = sqrt[s(s-a)(s-b)(s-c)], where s=(1/2)(a+b+c). The area can be rewritten as:

Area = sqrt[(1/16)(a+b+c)(a+b-c)(b+c-a)(c+a-b)], how can odd number be divisible by 16?