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Soarer
Frequent VisitorJoined: 18 Jan 2004Posts: 229
Location: Hong Kong
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Posted: Sat May 07, 2005 5:33 pm Post subject: Exponent
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How to compute , where k is not an integer? If k is a irrational, i don’t know how to compute. If k is a rational, i have a question.
which one is correct? |
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iene
Joined: 02 Jun 2004Posts: 4
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Posted: Sat May 07, 2005 8:51 pm Post subject:
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Because 1^1/6= 1 or -1
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yptsoi
Frequent VisitorJoined: 24 Jan 2004Posts: 51
Location: Hong Kong
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Posted: Sat May 07, 2005 10:51 pm Post subject:
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iene wrote:
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| Because 1^1/6= 1 or -1 |
I dont think so.
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Moron
Joined: 04 May 2005Posts: 5
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Posted: Sun May 08, 2005 8:50 pm Post subject:
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i think it should be +i and -i_________________
Moronism
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Andy
Frequent VisitorJoined: 28 Oct 2003Posts: 495
Location: Hong Kong
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Posted: Mon May 09, 2005 12:56 am Post subject:
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For any non-integral value k, we have to consider as a complex-valued power function.
We write as for convenience. Note that for all integers n, so is a multi-valued function and its set of values is .
For example, .
_________________
Patience and tolerance are necessarily demanded Year-round.
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Soarer
Frequent VisitorJoined: 18 Jan 2004Posts: 229
Location: Hong Kong
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Posted: Mon May 09, 2005 1:35 am Post subject:
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Thanks.
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