Math Forum :: View topic – indices

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bigKID

Joined: 18 Jul 2004Posts: 6

Posted: Wed Jan 05, 2005 4:06 pm    Post subject: indices

simplify and express the ans with +ve indices [4(3)^k-27(3)^(k-1)]/[3^(k-1)-3^(k+1)]*[1/9^(-k)]

thx

Wilson

Frequent VisitorJoined: 20 Oct 2004Posts: 74

Posted: Thu Jan 06, 2005 3:03 pm    Post subject: Re: indices

bigKID

Joined: 18 Jul 2004Posts: 6

Posted: Thu Jan 06, 2005 6:22 pm    Post subject: ..

ur ans is wrong..

Wilson

Frequent VisitorJoined: 20 Oct 2004Posts: 74

Posted: Thu Jan 06, 2005 7:03 pm    Post subject: Re: ..

bigKID wrote:

ur ans is wrong..

How about this?

bigKID

Joined: 18 Jul 2004Posts: 6

Posted: Fri Jan 07, 2005 1:41 pm    Post subject: .

many ppl got the same ans as urs.. the ans is -9/8

i dunno how to get it

Andy

Frequent VisitorJoined: 28 Oct 2003Posts: 391

Location: Hong Kong

Posted: Fri Jan 07, 2005 3:09 pm    Post subject: Re: .

bigKID wrote:

many ppl got the same ans as urs.. the ans is -9/8

i dunno how to get it

The powers of 3 do not agree if the answer is independent of k. I think you have typed the question wrongly. By the way, please do not cross post the same question in more than 1 section._________________

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