Posted: Thu Jan 06, 2005 6:49 pm    Post subject: indices, very simple

actually not high sch lvl..very simple [4(3)^k-27(3)^(k-1)]/[3^(k-1)-3^(k+1)]*[1/9^(-k)] [x^(2/3)y^(1/3)+x^(1/3)y^(2/3)]/[x^(4/3)y^(-1/3)+x] simplify and answer wif +ve indices

thx

Posted: Thu Jan 06, 2005 11:01 pm    Post subject:

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Posted: Fri Jan 07, 2005 1:39 pm    Post subject: ..

thx for ur ans but.. the ans of the first question is -9/8

would u plz do it again?

Posted: Fri Jan 07, 2005 3:06 pm    Post subject: Re: ..

The powers of 3 do not agree if the answer is independent of k. I think you have typed the question wrongly. By the way, please do not cross post the same question in more than 1 section._________________

Patience and tolerance are necessarily demanded Year-round.

Posted: Fri Jan 07, 2005 11:51 pm    Post subject: ..

Andy: sorry…