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alphaboy
Frequent VisitorJoined: 26 Nov 2004Posts: 37
Location: SFXS,TW
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Posted: Tue Dec 28, 2004 4:28 pm Post subject: BINOMIAL THEOREM
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Expand (1+x-3x^2)^6 = 1+6x-3x^2-70x^3+… But, how to find the constant term in the expansion of (1+x-3x^2)^6(1-1/x)^3 ?_________________
1+1= 2 or 1+1=11 (rejected)
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Wilson
Frequent VisitorJoined: 20 Oct 2004Posts: 74
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Posted: Tue Dec 28, 2004 9:01 pm Post subject: Re: BINOMIAL THEOREM
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alphaboy wrote:
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| Expand (1+x-3x^2)^6 = 1+6x-3x^2-70x^3+…
But, how to find the constant term in the expansion of (1+x-3x^2)^6(1-1/x)^3 ?
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constant terms occur at
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