請大師看看我有沒有計錯,謝謝 Question : a) In order to test the hypothesis that people of different religious affiliations tend to vary with respect to family size, five families were selected at random from each of three religious affiliations: Protestant, Catholic and Buddhist. The following three groups of families are shown in terms of their number of family members (parent and children both). Protestant Catholic Buddhist 2 6 3 5 7 2 4 8 4 3 6 4 5 4 3 Test the hypothesis at 5% significance level and state any assumption you need for your test. b) The personnel manager is concerned about absenteeism. (S)he decides to sample the records to determine if absenteeism is distributed evenly throughout the six day work week. The sample results are: Weekday Monday Tuesday Wednesday Thursday Friday Saturday No. Absent 12 9 11 10 9 9 Test whether or not absenteeism is distributed evenly throughout the week at 1% significance level. Answer (a): Source SS(Sum of square) df Mean of SS F-Statistic Between group 25.5 k-1 =3-1 =2 =SS/df =25.2/2 =12.6 =Mean of SS Between group/ Mean of SS within group 12.6/1.53 =8.24 Within group Total-Between group =43.6-25.2 =18.4 Total-Between group =14-2 =12 1.53 Total S.D * n =43.6 N-1 =14 n1=5 n2=5 n3=5 T1=19 T2=31 T3=16 SS between group = sum (Ti/ni) square – (sum X) square/N =(19) square/5 + (31) square/5 + (16) square/5 – (66) square/15 =25.2 I found on the F-statistic table , I found the row 2 and column 12 and get F =3.7389 . Therefore,8.24 > 3.7389 , H0 rejected. 是不是 between group/within group < 1 , rejected region在右面 而 between group/within group > 1, rejected region 在左面 我搞不清楚rejected region幾時在左面, 幾時在右面. Answer (b) 是不是 n1=1 ,n2=1, n3=1, n4=1 , n5=1, n6=1 T1=12,T2=-3,T3=2,T4=-1 , T5=-1,T6=0 = sum(Ti/ni) square – (sum X) square/N =(12) square +(-3) square + (2) square +(-1) square + (-1) square + (0) square – (60) square/15 =-81 rejected H0