|
| Author |
Message |
|
alphaboy
Frequent VisitorJoined: 26 Nov 2004Posts: 43
Location: SFXS,TW
|
|
Posted: Tue Dec 28, 2004 4:28 pm Post subject: BINOMIAL THEOREM
|
|
|
|
Expand (1+x-3x^2)^6 = 1+6x-3x^2-70x^3+… But, how to find the constant term in the expansion of (1+x-3x^2)^6(1-1/x)^3 ?_________________
1+1= 2 or 1+1=11 (rejected)
|
|
|
|
|
|
Wilson
Frequent VisitorJoined: 20 Oct 2004Posts: 79
|
|
Posted: Tue Dec 28, 2004 9:01 pm Post subject: Re: BINOMIAL THEOREM
|
|
|
|
alphaboy wrote:
|
| Expand (1+x-3x^2)^6 = 1+6x-3x^2-70x^3+…
But, how to find the constant term in the expansion of (1+x-3x^2)^6(1-1/x)^3 ?
|
constant terms occur at
|
|
|
|
|
|
|
|
All times are GMT + 8 Hours
|
|
| |
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
|
|