Math Forum :: View topic – digits

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mmrproblem

Joined: 05 Nov 2004Posts: 15

Posted: Fri Nov 26, 2004 4:50 am    Post subject: digits

Let xyz be a number with three digits.(base 10).Find all xyz
numbers that satisfy xyz=100x+10y+z=x^3+y^3+z^3

Wilson

Frequent VisitorJoined: 20 Oct 2004Posts: 74

mmrproblem

Joined: 05 Nov 2004Posts: 15

Posted: Sat Nov 27, 2004 4:43 am    Post subject: digits

Thank you Wilson,but I don’t know Chineese.Any site in English?

Curtiss20184

Frequent VisitorJoined: 30 Aug 2004Posts: 38

Location: HK F7

Posted: Sat Nov 27, 2004 6:50 pm    Post subject:

I found one more solution for the 11digits .
It is 32164049651 ….it is quite easy to found if you have a solution end with 0 as the rightest digit. _________________

I am a Form 7 Student in Hong Kong.

Last edited by Curtiss20184 on Sat Nov 27, 2004 6:57 pm; edited 1 time in total

Curtiss20184

Frequent VisitorJoined: 30 Aug 2004Posts: 38

Location: HK F7

Posted: Sat Nov 27, 2004 6:57 pm    Post subject:

Curtiss20184 wrote:

I found one more solution for the 11digits .
It is 32164049651 ….it is quite easy to found if you have a solution end with 0 as the rightest digit.

_________________

I am a Form 7 Student in Hong Kong.

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